y^2+1y+36=

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Solution for y^2+1y+36= equation:


Simplifying
y2 + 1y + 36 = 0

Reorder the terms:
36 + 1y + y2 = 0

Solving
36 + 1y + y2 = 0

Solving for variable 'y'.

Begin completing the square.

Move the constant term to the right:

Add '-36' to each side of the equation.
36 + 1y + -36 + y2 = 0 + -36

Reorder the terms:
36 + -36 + 1y + y2 = 0 + -36

Combine like terms: 36 + -36 = 0
0 + 1y + y2 = 0 + -36
1y + y2 = 0 + -36

Combine like terms: 0 + -36 = -36
1y + y2 = -36

The y term is 1y.  Take half its coefficient (0.5).
Square it (0.25) and add it to both sides.

Add '0.25' to each side of the equation.
y + 0.25 + y2 = -36 + 0.25

Reorder the terms:
0.25 + y + y2 = -36 + 0.25

Combine like terms: -36 + 0.25 = -35.75
0.25 + y + y2 = -35.75

Factor a perfect square on the left side:
(y + 0.5)(y + 0.5) = -35.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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